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Pythagoras' Theory proved using hexagons Pythagoras' Theory states that the square on the hypoteneuse of a right-angled triangle is equal to the sum of the squares on the other two sides. ![]() ![]() This all sounds very square, and the Hall of Hexagons wishes to point out that hexagons can be used to prove the theory thus:- ![]() We duplicate a hexagon; the area in each half is identical at each stage, until we find that the squares built on a and b together equal the square built on c (this is my own fun proof, rather similar to a proof usually ascribed to Leonardo). For other proofs, click here One way to look at the Pythagoras theory is to draw a line across a corner of a square:- ![]() Pythagoras' theory says that: Of course you'll want to know what happens when we draw a line across a corner of a hexagon:- ![]() Instead of a right-angle in the usual Pythagoras triangle, we have 120 degrees. The formula is:- ![]() For some reason this elegant result doesn't seem to be well known. It can be easily proved, knowing the formula for a right-angled triangle. What happens when we draw a line across two corners of a hexagon?:- ![]() By extending the sides of the hexagon (shown dotted) we have a 60 degree triangle, and the formula is:- ![]() Another simple but often overlooked result. Proof here. In fact, the general formula for a triangle with angle theta is: ![]() Proofs:- 120 degree triangle, with sides a, b and c:- ![]() ![]() 60 degree triangle, with sides a, b and c:- ![]() ![]() | ||||
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